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a.amitgarg
 
Posts: 6
Joined: Thu Mar 05, 2009 3:24 am
 

challenging question 05/23/05

by a.amitgarg Wed Nov 25, 2009 8:47 am

In the explanation, the possible values of p is considered as 0 < p < 100 which is incorrect since p cannot be greater than 6: Reason being Revenue is p(6-p) thousands and anything greater than 6 would mean negative Revenue. IMO, probability should be calculated with possible values of p as 0<p<6. Please let me know if i am missing anything.
Ben Ku
ManhattanGMAT Staff
 
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Joined: Sat Nov 03, 2007 7:49 pm
 

Re: challenging question 05/23/05

by Ben Ku Thu Dec 03, 2009 2:06 am

Please read (and follow!) the forum guidelines before posting. Please type out the entire question, including the answer choices, using the first few words as the Subject.

http://www.manhattangmat.com/forums/read-before-you-post-mgmat-math-strategy-guide-guidelines-t2721.html
Ben Ku
Instructor
ManhattanGMAT