Data Sufficiency Question from Official GMAPTPrep CD

[Venu]

Data Sufficiency

If z is the median of any 3 positive integers x, y and z then

i) x<y+z
ii) y=z

a) i only is sufficient and ii is not
b) ii only is sufficient and i is not
c) i and ii together are sifficient
d) Both
e) none

Thanks !

[shaji]

Seems that the DS is incomplete!!!

Data Sufficiency

If z is the median of any 3 positive integers x, y and z then

i) x<y+z
ii) y=z

a) i only is sufficient and ii is not
b) ii only is sufficient and i is not
c) i and ii together are sifficient
d) Both
e) none

Thanks !

[StaceyKoprince]

Yep - there isn't actually a question here! Please check the text of the question and repost. Also, just FYI for future, because the answers are always the same for DS problems, you don't need to list them (but you still do for any other type of problem).

[dr_o]

I guess the question was (Is and not If):

Is z the median of any 3 positive integers x, y and z?

i) x<y+z
ii) y=z

If that is that case.

i) is insufficient. there is not enough information on the values of x,y,z.
ii) is sufficient. there are 3 possibilities: x<y=z, x=y=z, y=z<x. in any case z is the median.

Hence the answer is B

[RonPurewal]

I guess the question was (Is and not If):

Is z the median of any 3 positive integers x, y and z?

i) x<y+z
ii) y=z

If that is that case.

i) is insufficient. there is not enough information on the values of x,y,z.
ii) is sufficient. there are 3 possibilities: x<y=z, x=y=z, y=z<x. in any case z is the median.

Hence the answer is B

i couldn't have put it better myself.

if you need convincing about answer a, then remember that your goal on these types of problems is to try to prove 'maybe' (i.e., insufficient). so try to find 2 groups of numbers, one of which gives a 'yes' answer and one of which gives a 'no' answer:
(x, y, z) = (1, 3, 5): z is not the median
(x, y, z) = (1, 5, 3): z is the median
bam! insufficient.