Hi Ron,
The following question was given as part of homework on the 3rd Nov, 2011 session:
There are 6 consecutive positive integers in the set S. What is the value of the positive integer n?
1. When each integer in S is divided by n, the sum of the remainders is 11.
2. When each integer in S is divided by n, the remainders include five different values.
The answer is B.
Though I solved the above problem (couldn't solve it in 3 mins - It took me far beyond 3 mins to get the answer), I faced great difficulty in figuring out the following:
1. I had to try in-numerous options to find the remainders that would sum to 11 (considering the integers in S are consecutive).
After cracking my head for quite some time I figured out that remainders 3 2 1 0 3 2 would sum up to 11 and the integers will be consecutive.
2.After this, I checked for some random values of n to see if st. 1 is satisfied or not. I agree that once I figured out the above thing, it was easier to test different integers for n and solving st. 2.
Now, as stated by you in the video to try some variations such as 12, 13, 14 etc. in st.1 and figure out the answer.
When I tried solving with the other variations, I was once again cracking my head to get the combination of remainders which would sum to 12, 13 etc. and would be consecutive. As usual, I again could not solve it in 3 mins.
Is there any other approach to these problems or it can only be solved by randomly trying out various combinations that would sum to a particular no. ,i.e., the sum of the remainders = 11 or 12 or 13 etc.