by StaceyKoprince Mon Dec 10, 2007 8:23 pm
It's highly unlikely that you will have the time to use a quant approach to standard deviation on the test. Without a calculator, this just isn't something you can do in 2 min. For SD, then, it's important to make sure you understand the concepts so that you can use Ron's qualitative approach - that will be sufficient for SD questions b/c they know the formula is too complicated to be done on paper in 2 min.
And to answer your first question - we don't actually know for sure that it will not decline (or that it will!) unless we know something about the values in the set. (This is true for all the other options, not E.)
The problem tells us that D is positive - that is, there is a standard deviation (the other option is for it to be zero, in which case every number in the set is identical). If there is a standard deviation, that means that the numbers are not all identical - at least one is different.
So, let's say I have 0, 6, and 12. The average is 6, and there is some positive standard deviation, because the numbers are not all equal to the average. Note that only the 0 and the 12 contribute mathematically to the positive standard deviation. The 6 contributes an "SD value" of zero, because it is identical to the average, and the SD is a measure of the difference between any number in the set and the entire set's average.
Now, if I add two more 6's to the set, I'll have 0, 6, 6, 6, and 12. This will still have a positive standard deviation, because all of the numbers are not 6, but the standard deviation will be smaller than it was in my first group of three numbers because there are three 6's in this group - so three out of five numbers are identical to the average now, and all three are contributing "SD values" of zero, while only two numbers (0 and 12) are contributing to some positive SD. So the overall SD here will be smaller than it was in the example in the previous paragraph because the three 6's are "outweighing" the 0 and the 12 (more so, at least, than one 6 does).
Stacey Koprince
Instructor
Director, Content & Curriculum
ManhattanPrep