True, you don't take a prime factorization of zero. Zero is a special case, so just consider it separately.
Zero is a multiple of every integer. (Specifically, for any integer n, zero is zero times n.)
So, the remainder when zero is divided by any integer"”including 24"”is zero.
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- RonPurewal
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- RonPurewal
- Students
- Posts: 19744
- Joined: Tue Aug 14, 2007 8:23 am
Re: Re:
More importantly, GMAC does not write problems on which "special" or "exceptional" cases change the answer.
In other words, if you don't know what the deal is with the remainder of 0/24, you can just ignore that case. The answer to the problem will turn out the same as it would if the case were included. (Here, it's C both ways.)
Here are some examples of the kinds of "exceptional" or "weird" cases I'm talking about:
* Negative odds and evens
* 1 is not prime
* Remainders of m/n where m < n (in this case the remainder is just m, but I've never seen a problem depending on this)
In fact, even if GMAC wrote such a problem, it wouldn't even make it onto the real exam, because it wouldn't pass the experimental phase. (If a problem like that were "crowdsourced", the crowd wouldn't pick answers in any pattern that would correlate meaningfully with scores.)
In other words, if you don't know what the deal is with the remainder of 0/24, you can just ignore that case. The answer to the problem will turn out the same as it would if the case were included. (Here, it's C both ways.)
Here are some examples of the kinds of "exceptional" or "weird" cases I'm talking about:
* Negative odds and evens
* 1 is not prime
* Remainders of m/n where m < n (in this case the remainder is just m, but I've never seen a problem depending on this)
In fact, even if GMAC wrote such a problem, it wouldn't even make it onto the real exam, because it wouldn't pass the experimental phase. (If a problem like that were "crowdsourced", the crowd wouldn't pick answers in any pattern that would correlate meaningfully with scores.)