information booklet

[ASMAA997]

Two teams are distributing information booklets. Team A distributes 60% more boxes of booklets than Team B, but each box of Team A’s has 60% fewer booklets than each box of Team B’s. Which of the following could be the total number of booklets distributed by the two groups?

2,000
3,200
4,100
4,800
4,900


I assumed that A box = 10 therefore, b= 4, ( 10/4 ) = ( 5 / 2 )
so we have the min. # of Boxes for A = 5 and for B = 2

# of books assumed B = 15, therefore : A = 9 ; ( 9/15 )

5*9: 15*2
45 : 30
/ 15
to get min value divide be common factor
3 : 2
add them = 5

all the choices are multiple of 5. I tried many numbers.
So I need help

[RonPurewal]

you have the right idea --

60 percent MORE BOXES = 160% as many boxes
...ratio of boxes = 160:100
= 16:10
= 8:5

60 percent FEWER ITEMS PER BOX = 40% as many items per box
...ratio of items per box = 40:100
= 2:5

so, team A distributed 8/5 times as many boxes, with 2/5 as many items per box... that's 8/5 · 2/5 = 16/25 times as many items as team B distributed.

...so here's the thing:
team B distributed 25/25 times as many items as team B did.
(:

so, TOGETHER, the two teams distributed 25/25 + 16/25 = 41/25 times as many items as just team B did. so, you need a multiple of 41.

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how does the ANSWER KEY work?
if this is one of our problems, there should be an answer key -- i'm guessing that should shed at least some light on these issues.