Machines A and B each produce tablets at their respective constant rates. Machine A has produced 30 tablets when Machine B is turned on. Both machines continue to run until Machine B’s total production catches up to Machine A’s total production. How many tablets does Machine A produce in the time that it takes Machine B to catch up?
(1) Machine A’s rate is twice the difference between the rates of the two machines.
(2) The sum of Machine A’s rate and Machine B’s rate is five times the difference between the two rates.
Questions:
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It is simple if we consider that the speed of B is greater than that of A. What about the other way where the machine B cannot catchup ?
Am I missing any that derives this assumption?
OA is D
- as both alone can help to resolve the problem.
but if it is not implied (B>A) , then we can derive this from using BOTH 1& 2 , making it Option C.