cooper2248817 Wrote:Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 30 white marbles. How many red marbles could be in bag A?
a.1
b.3
c.4
d.6
e.8
I just don't seem to understand multiple ratios such as in this questions. Please help
Is this method logical?
The ratio of R:W:B balls in bag A is 2:6:9 and R:W in bag B is 1:4. Then, 6x+4y=30. Now consider the various answer options.
a)R(a)=1, not possible as it must be a multiple of 2 WRONG
2) Same reasoning as above does not let us take R(a)=3. WRONG
3) r(a)=4, implies actual number of balls of different colors in bag A is 4:12:18. This means bag B has 30-12=18 balls. 4y=18.18 is not divisible by 4 the number of white balls in B must be perfectly divisible by 4. WRONG
4) r(a)=6, thus the number of balls in A is 6:18:27. Thus, number of white balls in B is 30-18=12. 4y=12, which gives an integer value of Y. So possibly correct
5)R(A)=8, thus the ratio of balls in A becomes 8:24:36. Thus the white balls in B is 30-24=6. 4Y=6 does not give an integer value of Y and hence WRONG.
Thus the answer must be d.