RonPurewal Wrote:...and actually those 2 cases prove that the answer is E, since both of them also satisfy statement 1.
so now i'm really interested in seeing this answer key. how does it (supposedly) show that statement 2 is sufficient?
Yup i guess they did a mistake of considering only one case.
Here is the solution written.
" Standard deviation is a measure of the spread of a group of numbers.
1) INSUFFICIENT: If set M contains { 1,2,3,4,5,6,7}, then 4 is the median. Set N could be {3,4,5}, which has a smaller standard deviation than set M because the two sets have the same average but N is not as spread out as M .
Alternatively, N could be {1,4,7} which has larger standard deviation than set M because the two sets still have the same average , but N is now more spread out than N . (It doesn't have additional values that are closer to the average )
2) SUFFICIENT : if set M contains the numbers {1,2,3,4,5,6,7} and set n has the same range , then N must contain 1 and 7 . if set N contains {1,4,7} then N has a larger SD than M . if set N contains {1,2,7} the standard deviation actually increases even more ( because the numbers are no longer evenly distributed). No matter what combination you try, the standard deviation of N has to be greater than SD of M.The correct answer B
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Also, Ron these workout sets are of 700+ level questions please through some light on as to how much time should i take solving each set of 10 questions.
Currently I am taking 25-30 mins . (more time when a problem of sequence is there requiring cases to be written down and adding the terms( no formula could be applied) ; and geometry problems which requires a lot of visualization ( again where no formula could be applied ).
So i guess these problems are meant to take 3 mins .
So, i was wondering then in real gmat as the level increases time might turn out to be a constraint.
Currently, I am scoring q48 in gmat prep consistently(no time issues ). Curious to know how to make it to q51.
I know the question is very broad and vague . But if u could answer it somehow might turn out to be helpful for me .