lionheart Wrote:Which of the following inequalities has a solution set that, when graphed on the number line, is a single line segment of finite length?
A) x^4 >=(greater than or equal to) 1
B) x^3 =< 27
C) x^2 >= 16
D) 2 =< abs(x) =< 5
E) 2 =< 3x + 4 =< 6
Answer is E, don`t understand why it cant be D
This question is a GMAT Prep question and has already been discussed in the following link:
http://www.manhattangmat.com/forums/whi ... -t793.html
But basically, options A, B and C are out as they are non-linear.
D gives us 2 sets of solution sets when x is either positive or negative. When you solve you will get the following:
-5<=x<=-2 and 2<=x<=5
E is reduced to the inequality, -2/3<=x<=2/3. This gives just 1 solution set and hence is the correct answer.
Note that inequalities always gives us an area when plotted on a graph. I had trouble understanding how an area can be compared with a single line segment of finite length, as was being asked in the question, until I focussed on the part of the question that says 'when graphed on the number line'. GMAT has very cleverly put this in order to confuse anyone who can fall into this trap. So basically, when the solution set is plotted on the number line, it is reduced to a line segment which would be of finite length for linear inequalities.