This problem is from the Geometry Strategy Guide, Chapter 2, problem #7:
Two sides of a triangle are 4 and 10. If the third side is integer x, how many possible values are there for integer x?
Answer: 7
If two sides of a triangle are 4 and 10, the third side must be greater than 10 - 4 and smaller than 10 + 4. Therefore, the possible values for x are {7, 8, 9, 10, 11, 12, 13}.
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My Question:
I rationally understand that when I list the values out from 6 to 14, that there are 7 integer values, but I got the question wrong because I did 14 - 6 = 8.
How do I conceptually understand this? Am I not accounting for some kind of double counting?
Thank-you for your help in advance!