Great questions,
elanaminkoff!
This is an interesting
hybrid game - we have to
group the elements into first and second segments, but then within each segment, those elements must be
ordered.
The first two rules lay out how the ordering and grouping relate to one another. The first rule tells us the grouping task: first group has 3 slots, second group has 2 slots. The second rule introduces the ordering element - but notice that it says "
within each segment". So the ordering
only applies within each group.So, when we find out later that International is always longer than weather, that means that Int'l must come first
if they are in the same group. If they aren't in the same group, it doesn't matter what slots they go in!
The first thing to do is just get a sense of the shape of the setup. We've two groups, and each group is being
independently ordered (by length). So, we can set up two sets of ordered slots, like this:
Our elements are also grouped already into general interest (I and N) and local interesting (s, t, w). We can use upper and lowercase letters to quickly visually distinguish these.
Next, we need to deal with the implication of each rule. We've handled the first two, just to understand the setup. Rule #3 tells us that each segment needs at least one local interest element (s, t, w). But we can't just assign a spot to be local interest in each group, since they are
ordered slots.
Instead, let's think about each group. The first group has 3 slots, and there are only two general interests, so no matter what we do, it will always have a local interest - that's covered. But what about the second group? It only has two slots - so if we put both
I and
N in the second group, we'd never get a local interest in there.
Ah ha! Rule #3 is really just telling me that
I and
N can't be together in the second group! (see diagram below).
Rules #4 and #5 are way easier to deal with.
N is the longest, and that means that it will come first
in whatever group it is in. Similarly,
s is the shortest, so it will come last
in whatever group it is in.
Finally, rule #6 tells us that
I is longer than
w, so that will mean that
I is
before w,
if they are in the same group (as discussed above).
Getting a strong handle on these somewhat unusual rules is the key to this game. Unfortunately, though, there's really not a lot to put into the master diagram. However, it is interesting to note that since
N must always be the first of its group, there are only two spots it can occupy (first of the first segment, or first of the second segment. Similarly,
s can only be last of the first segment or last of the second segment.
I'm a bit of a framing fanatic, so I was inclined to quickly sketch out four frames around these two binaries. This isn't necessary, and in fact the only really interesting frame that results here is the last one:
N and
s together in the second group forcing everyone else to the first group. But it gave me a quick visual playground in which to try out answers on a few of the questions.
Again, framing is a preference here, and certainly not a necessity. The really critical things are to 1) understand how the ordering and grouping relate to one another and 2) get a handle on the unusual rules.
Please let me know if that helps clear things up a bit!