Q11

[OliviaB660]

Hey, I'm looking at the posted diagram and I'm still very confused by this question. I understand why the F placement leads to the L placement and the K placement, and we already have G placed. But how do we know where H & M go, aside from not with K or with I? I thought it might have something to do with the S & T numerical distribution requirement, but I can't figure it out.

[Misti Duvall]

You're right to be thinking about the numerical distribution, so let's break this down. Here's what we know to start:

R: F L
S: __ __
T: __
U: G

How do I know group S has 2 and group T has 1? Since group S has to have more than group T, and everyone else has to have at least 1, the only possibilities are S = 3 / T = 2 or S = 2 / T = 1. If group S has 3 and group T has 2, that only leaves 1 each for groups R and U. But, because of the F and L rule, we already know group R has at least 2. So the breakdown is going to have to be S = 2 / T = 1.

From there, the next limited element is K, since it has to be by itself. Since G is in group U already, the only place for K is in group T.

And, finally, I can't go with either H or M, meaning H and M are going to have to go together in group S, because it needs 2 elements. And I can then go in group R or group U. So the final diagram looks like this:

R: F L I/
S: H M
T: K
U: G /I

Everything has a set place except for I, so 5 of the elements other than F are locked in, which is answer choice (E).