Q11

[ManhattanPrepLSAT2]

Here is a solution for this problem

[Mtfitzgerald5]

Thank you for the explanation and I do understand the logic. That being said, I need to figure out the fastest way to solve this; should I just pick answer choices and just start mapping or is their a faster way to go about this question. I just want to possibly see what I am missing.

If you could shed some light on how you quickly got to the answer choice that you mapped, that would be golden.

Thanks.

[ohthatpatrick]

An open-ended question like this (Unconditional) that appears towards the end of the game normally tests deeper 'deductions', if we can even call them that.

It tests some limitation on the game that no normal person would have ever discovered for themselves during the setup/inference stage.

So you always start by looking at all the work you've done on the IF (conditional) questions and seeing what you can eliminate.

You take a quick mental pass through all the remaining answers to see if any of them suddenly strike you as impossible.

And then you go right into plug and chug mode otherwise (very common for me, and I've been taking LSATs for over 8 years).

For Q8, we may have had a scenario like
K O L | J N

(I'm listing V, Y, Z, out, out)

For Q9, we may have had
O N L | K J

For Q10
J K L/O | N O/L

So when we look at Q11, we can easily dismiss (D) and (E), since we just had a scenario where L or O could each be out.

Take a quick mental pass through A/B/C to see if any of them jump out at you, and otherwise get going with plug and chug.

When I'm picking which answer to start randomly trying, I lean towards any answer that automatically tells me something.

(A) immediately tells me that K is in and N and L are out, so I would try that one, but it turns out it's possible.
K O J | N L

(B) tells me that N and L are out, so that means J and O are in.
O J K | N L

If I'm in a hurry, I'll pick (C) from process of elimination.
If I have time, I'll confirm that it breaks.