Q12

[ChristinaF532]

This question took more time that it should've, can someone walk me through the process?

[ohthatpatrick]

There were some juicy upfront inferences available on this game, so this question goes speedily if we picked up on those.



V - O - M - F
...\
.....T

From that relative ordering tree, we know that V is first, O/T is second, O/M/T is third, M/T is fourth, and F/T is fifth.


We only get 1 premium, and
2nd = 3rd, (those can't be p)
and
the car before M and M both get r's.

Do we know that the 2nd/3rd match can't be p.
Can it be 's' or does it need to be r?

If we picture trying to do something where 2nd/3rd is 's', it could look something like
p - s - s - r - r

The problem is ... where is M?

M has to be 3rd or 4th. Either one of those would violate this p-s-s-r-r sequence.

Since M is going to be 3rd or 4th, we know we'll either have
V, O, M, T/F, F/T
or
V, O/T, T/O, M, F

In both cases, let's add (r) to M, and add (r) to the car immediately before M.
V, O(r), M(r), T/F, F/T
or
V, O/T, T/O(r), M(r), F

Since 2nd = 3rd, we can even update the bottom frame here to be
V, O/T(r), T/O(r), M(r), F

Since we know we need a super wash but it can't be 1st, and we know we need exactly one premium, we know the bottom frame has to be
V(p), O/T(r), T/O(r), M(r), F(s)

Because of these frames (the two possible spots for M), we learn that the 2nd wash will always be regular.

(A) doesn't have to be true in the first frame: V, O(r), M(r), T/F, F/T
V could be 'r' in that frame.

(B) Not true in our second frame. V(p), O/T(r), T/O(r), M(r), F(s)

(C) Doesn't need to be true in the first frame: V, O(r), M(r), T/F, F/T
5th car could be 'r' or 'p' in that frame.

(D) Not true in our second frame. V(p), O/T(r), T/O(r), M(r), F(s)

Hope this helps.

[CalvinC566]

I think you misread the prompt patrick.
The prompt for #12 says Vinquetta does NOT recieve a premium.
The answer is A
V-O/T-T/O-M-F
R-S-S-S-P
and
V-O-M-T-F
R-R-R-S-P