by ConnorL87 Mon Oct 29, 2018 2:48 pm
I just plugged things in, and luckily A was the first one I tried and it was correct. Plug K and S into Zone 1. Since S is always with U, that means K, S, U are going to be in Zone 1. Since Zone 2 has to be either T or SU, T has to be in Zone 2. But then that creates a problem for Zone 1 where we need to have PQ as well, since Zone 1 must have either PQ or T and now cannot have T. But an inference I got from the Big Pause was that Zone 1 cannot have more than 4, because that doesn't leave enough possible people to ensure that Zone 3 has at least one more person than Zone 2. So (A) must be false.