by ohthatpatrick Mon Jul 31, 2017 12:25 am
Hey, Christine.
There are some decent upfront deductions in this game that help. We have ...
H L P R S
~(SP)
(HR)
L = M or T
If P-v, then H-v
No student is alone
Since no student is alone, and we have to put 5 things into 3 shoeboxes, we basically HAVE to have 3-2-0
3 in one box, 2 in one box, 0 in the other.
Our usual "distribute 5 things into three groups" options don't apply
3 1 1
2 2 1
since we can't have a 1.
So who is our threesome and who is our twosome?
We have an HR chunk. Could that be the twosome and LPS the threesome?
No, because S and P can't be together.
So we'll have to have a threesome: H, R, S/P
and a twosome: L, P/S
This kills choices C, D, and E very quickly on Q4.
We only need to check (A) and (B).
(A) if P is in V, then H is in V, so we'd have
HRP in Vancouver and LS in Montreal or Toronto.
Hence, (A) could be false. S doesn't HAVE to do Montreal. LS could be in Toronto.
Meanwhile, (B) must be true.
If P is in V, then we know we have HRP in Vancouver.
Hope this helps.